Well, you don’t want to take away the 0 and 1. Rather, take away the 8 and 9 and you have octal.
Today’s puzzle has 4 solutions. How many can you find?
Were you able to figure out yesterday’s puzzle?
\begin{align*}
C & = [2, 2, 5, 9, 10, 10, 12]\cr
E & = [9, 9, 4, 1, 4, 4, 9]\cr
H & = [1, 1, 2, 3, 3, 3, 3]\cr
R & = [0, 10, 13, 13, 7, 13, 4]\cr
S & = [11, 6, 6, 12, 2, 0, 11]\cr
U & = [8, 7, 3, 11, 11, 9, 13]\cr
X & = [5, 3, 10, 15, 6, 2, 5]\cr
\end{align*}
And here’s today’s puzzle! Leave a comment if you’ve solved it! Scroll down further if you want a hint [spoiler free].
Want a hint?
\begin{align*}
C& = 2\cr
\end{align*}
